let myString = "#12345678"
        let myfind: Character = "#"
        if let idx = find(myString, myfind){
        var myNewString = myString.substringWithRange(( advance(myString.startIndex,0+1)..<advance(myString.endIndex, 0)))
        }

Output:
12345678
Screen Shot 2015-02-22 at 8.48.36 AM

let myString = "[ABCDEFGHI]"
        let startIndex = advance(myString.startIndex, 1)
        let endIndex = advance(myString.endIndex, -1)
        let range = startIndex..<endIndex
        var myNewString = myString.substringWithRange( range )

Output:
ABCDEFGHI

Screen Shot 2015-02-22 at 8.50.20 AM

By admin-powenko

Dr. Powen Ko is a teacher and CEO on LoopTek LLC, and like to teaching. if you need to class, please let PowenKo know, he will love to service and sharing. LoopTek web site is www.looptek.com

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