How to sort a Map<Key, Value> on the values in Java?
I am relatively new to Java, and often find that I need to sort a Map on the values. Since the values are not unique, I find myself converting the keySet into an array, and sorting that array through array sort with a custom comparator that sorts on the value associated with the key. Is there an easier way?
answer is below.
package com.powenko.Tutorial_Fun_HashMap;
import java.util.Arrays;
import java.util.Comparator;
import java.util.HashMap;
import java.util.Iterator;
import java.util.LinkedHashMap;
import java.util.Map;
import java.util.Set;
import android.app.Activity;
import android.os.Bundle;
public class Tutorial_Fun_HashMapActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
///////
Map<String, String> map = new HashMap<String, String>();
map.put("Cde", "C");
map.put("Abc", "A");
map.put("Cbc", "Z");
map.put("Dbc", "D");
map.put("Bcd", "B");
map.put("sfd", "Bqw");
map.put("DDD", "Bas");
map.put("BGG", "Basd");
System.out.println(sort(map, new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
return o1.compareTo(o2);
}}));
String t1=map.get("BGG");
String t2=map.get("Abc");
}
@SuppressWarnings("unchecked")
public static <K, V> Map<K,V> sort(Map<K, V> in, Comparator<? super V> compare) {
Map<K, V> result = new LinkedHashMap<K, V>();
V[] array = (V[])in.values().toArray();
for(int i=0;i<array.length;i++)
{
}
Arrays.sort(array, compare);
for (V item : array) {
K key= (K) getKey(in, item);
result.put(key, item);
}
return result;
}
public static <K, V> Object getKey(Map<K, V> in,V value)
{
Set<K> key= in.keySet();
Iterator<K> keyIterator=key.iterator();
while (keyIterator.hasNext()) {
K valueObject = (K) keyIterator.next();
if(in.get(valueObject).equals(value))
{
return valueObject;
}
}
return null;
}
}
sample code:
Tutorial_Fun_HashMap